$\left(a^{12}+b^2\right)\left(a^2-b^2\right)$

$9x^2+12xy+4x$

$1-\sin^2\left(x\right)=\left(1-\sin\left(x\right)\right)\left(1+\sin\left(x\right)\right)$

$\frac{dy}{dx}\:+3y=-10e^{-2x}$

$13\left(b+1\right)-6-3b-5$

$5^{15}.\:5^{17}.\:5^{-30}.\:5^{11}.\:5^{-10}$

$x\cdot\frac{dy}{dx}=y+1$