$\int\frac{\left(x^2+3x+2\right)}{x\left(x^2+2x+2\right)}dx$
$\sin^2x+5\sin x+4$
$-2\left(x+4\right)\left(x-4\right)$
$\lim_{x\to0}\:\frac{1-tanx}{1-senx}$
$-1\left(x-8\right)+7\left(4-3x\right)$
$\int_2^8\left(8x^3+2x^2+12\right)dx$
$\left(-9u+v^2\right)\left(-9u-v^2\right)$
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