$y=\left(x+3\right)^2-7$
$\int\left(3x^2-4x+2\right)xdx$
$\frac{25x^5}{5x^2}$
$\sqrt[3]{x^2+4}=2$
$\int\:\frac{u}{u^4+2u^2+1}du$
$\left(x^2\:+\:2x\right)^4$
$-982+1500+-21+-65+-1021+257+-654+-635$
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