$9\left(a-b\right)^2$
$60\cdot\frac{3}{\sqrt[3]{9}}\quad65$
$\lim_{x\to\infty}\left(\frac{x^2+9x+5}{x^3-6x^2+3}\right)$
$\cos\left(a\right)-\frac{\sin^2\left(a\right)}{\cos\left(a\right)}$
$x^2-9x-3$
$5x-6=3x-8$
$\left(5+4y\right)^2$
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