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Solving: ddx(x3cos⁡(x)3(x+1)3)\frac{d}{dx}\left(\frac{x^3\cos\left(x\right)^3}{\sqrt{\left(x+1\right)^{3}}}\right)
Solve instead: dydx(x3cos3(x)(x+1)32)\frac{dy}{dx}\left(\frac{x^3cos^3\left(x\right)}{\left(x+1\right)^{\frac{3}{2}}}\right)
f(x)=(x^3cos(x)^3)/((x+1)^(3/2))−6−5−4−3−2−10123456−3-2.5−2-1.5−1-0.500.511.522.53xy

Exercise

dydx(x3cos3(x)(x+1)32)\frac{dy}{dx}\left(\frac{x^3cos^3\left(x\right)}{\left(x+1\right)^{\frac{3}{2}}}\right)

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Final answer to the exercise

(3x−3tan⁡(x)+−32(x+1))x3cos⁡(x)3(x+1)3\left(\frac{3}{x}-3\tan\left(x\right)+\frac{-3}{2\left(x+1\right)}\right)\frac{x^3\cos\left(x\right)^3}{\sqrt{\left(x+1\right)^{3}}}

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dydx (x3cos3(x)(x+1)32  )
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