$\frac{3x^3+6x^2}{3x}$
$y'=12xy-2x,y\left(0\right)=14$
$x+4y-8z=-8\:\:\:\:$
$\left(x^7-6\right)\left(x^7+3\right)$
$64x^2-16xy+y^2$
$\left(3x^3-2\right)^4$
$3\left(3^2\right)-2\left(1\right)+1$
Get a preview of step-by-step solutions.
Earn solution credits, which you can redeem for complete step-by-step solutions.
Save your favorite problems.
Become premium to access unlimited solutions, download solutions, discounts and more!