$\ln\left(y\right)-x\ln\left(x\right)=-1$
$\frac{dy}{dx}+xy=1$
$-5x\left(4-x\right)$
$\left(f-3\right)^2$
$6\left(4s+7\right)+8$
$\frac{d^2}{dx^2}\left(-7x^3-13y^5=3\right)$
$\tan x=-1$
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