$\sqrt[3]{24\left(x+1\right)^8z^2}$
$\frac{3x^3-8x^2+6x-5}{x+2}$
$\frac{dy}{dx}=\frac{4-2x}{3+2y}$
$\frac{x^4-3x^3+2x-3\:}{x^3-2}$
$\frac{3^{5m}}{3^{3m}}=81^{0.5m}$
$x^2+14x=4$
$a^0c^{-7}d^8$
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