$\sqrt[2]{4+\sqrt{15}}\cdot\sqrt{4-\sqrt{15}}$
$5x\left(2x-1\right)+3\left(2x-1\right)$
$\sqrt{\frac{1}{36}x^2}$
$7x\:+5x\:-2x\:-6x$
$8^7.8^{-12}$
$-3x^2+2y^2-7+10x^2-12y^2+15$
$\frac{x+8}{3}+\frac{x}{9}=x-4$
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