$\csc^2\left(x\right)-7\csc\left(x\right)+6=0$
$-9cos^2\left(x\right)+9=16sinx-7$
$\left(x-18\right)^2$
$ex=t+1$
$l\lim_{x\to1}\left(\frac{1}{x-1}-\frac{5}{x^2+3x-4}\right)$
$\left|\left(-13\right)^5\right|^4$
$\left(-9x+1\right)\left(-9x-1\right)$
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