$f\left(x\right)=4x\left(x+3\right)+2x$

$\frac{d}{dx}\left(\cot^2\left(\sin x\right)\right)$

$\frac{dy}{dx}=\left(3-x\right)\left(2+y\right)$

$\frac{4x^4+6x^2+8x+11}{-4x^2-2}$

$\frac{3x^2-2x^2+x-3}{3x+2}$

$2cos^2\left(x\right)-9cos\left(x\right)=-5$

$3.77\cdot0.375$