$z+z+8-10$

$12x+7y=0$

$3-5\cdot2+6\cdot4$

$\left(x+5\right)\left(x-5\right)\left(x^2+3\right)$

$\int\frac{8x^3+1}{4x^2-2x+1}dx$

$\frac{\sin^3\left(x\right)+\cos^3\left(x\right)}{\sin\left(x\right)+\cos\left(x\right)}-1=-\sin\left(x\right)\cos\left(x\right)$

$8.98+20.90+6.04+5.56+21.84+3.63$