$\frac{3m^3n^2-12m^2n^3+18mn^4+3m}{3mn}$
$x^3-4^2+x+6$
$\csc\left(x\right)\left(1+\tan^2\left(x\right)\right)$
$_{\left(x-2\right)}3$
$5^8\cdot5^3$
$\int_1^2\:\frac{x^2+x-1}{4x^3+6x^2-12x+3}dx$
$\left(r^2\right)^{-3}$
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