$x+4y=12$
$\left(mn-ml\right)\left(mn+ml\right)$
$\left(4-4\right)^2+\left(3+2\right)^2$
$\frac{3x^3-8x^2+6x+8}{x+4}$
$4b^2-16d^2$
$\int\left(2x^2+8\right)e^{3x}dx$
$\frac{x^2}{4}+\frac{9}{16}$
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