$-24\::-3$
$\left(-7\right)+\left(+4\right)+\left(-5\right)+\left(+3\right)+\left(-15\right)$
$\left(w^6\right)^5$
$\lim_{x\to\infty}\left(\frac{\sin\left(x\right)+100}{x^2+100}\right)$
$24a^2-4a-140$
$9x^2+30ax+25a^2$
$-2x+9>6$
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