$\left(x-4\right)^2\:\left(x-4\right)^2\:$
$\left(10m+6\right)^2$
$\frac{x^2+1}{x^2+3x+2}$
$14.29+10.43+5.42$
$\lim_{x\to3}\left(\frac{x+1}{x-2}\right)$
$\ln\left(0.00018\right)$
$-x^2+9x+9$
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