Final answer to the problem
$\frac{m^{18}-n^{18}}{\left(m-n\right)\left(m^2+mn+n^{2}\right)}$
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Step-by-step Solution
How should I solve this problem?
- Choose an option
- Write in simplest form
- Solve by quadratic formula (general formula)
- Find the derivative using the definition
- Simplify
- Find the integral
- Find the derivative
- Factor
- Factor by completing the square
- Find the roots
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1
Factor the difference of cubes: $a^3-b^3 = (a-b)(a^2+ab+b^2)$
$\frac{m^{18}-n^{18}}{\left(m-n\right)\left(m^2+mn+n^{2}\right)}$
Final answer to the problem
$\frac{m^{18}-n^{18}}{\left(m-n\right)\left(m^2+mn+n^{2}\right)}$
