$3y^2+4y-7$
$20-\left(15-8-6\right)+\left(5-7-4\right)$
$2y=6-x$
$\frac{3}{x\:}\le3$
$25x^2+16<40x$
$y\cdot\frac{dy}{dx}=\frac{e^x}{1+\left(e\right)^x}$
$\left(x^2+3x^2\right)^5$
Get a preview of step-by-step solutions.
Earn solution credits, which you can redeem for complete step-by-step solutions.
Save your favorite problems.
Become premium to access unlimited solutions, download solutions, discounts and more!