$x^2+8x=240$
$\frac{dy}{dx}=\frac{9+16x}{xy^2},y\left(1\right)=2$
$12-7+8-5-3+2-6$
$\left(4x-3x^3+2x^2-1\right)\cdot\left(4x+2x^2+3\right)$
$8\left(2x+5\right)-12$
$\left(t\:-\:4\right)^3$
$dy=-x\left(y^2+y\right)dx\:;\:y\left(2\right)=1$
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