$4^{-1}\cdot4^5$
$\sqrt{125x^5}$
$\frac{dy}{dr}=-1.5\cdot\left(y-y^3\right)$
$-\frac{1}{\cos^2\left(x\right)}-\frac{tan^2\left(x\right)}{cos^2\left(x\right)}=-\frac{1}{cos^4}$
$\frac{dy}{dx}=\frac{\left(2+x^2\right)y^2}{x^2}$
$t^2-20t$
$4f^2-16f+16$
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