$\left(x^2+1\right)+\left(4xy-x\right)y'=0$

$640-10x^2$

$-8\left(p-3\right)$

$\int_0^{\frac{\pi}{3}}\left(\frac{\left(-2sin\left(x\right)\right)}{cos^2\left(x\right)}\right)dx$

$\tan b+\frac{\cos b}{1+\sin b}=\sec b$

$\frac{dx}{dt}=\left(1+x\right)\left(1+t\right)$

$\frac{dy}{dx}=x^3\left(9-x^2\right)$