$1-12x+16x^2$
$25p^2-30p+9$
$2x+5+7x-4$
$\ln\left(x+4\right)-\ln\left(2\right)=4$
$2\left(x-4\right)-3=1+x$
$\lim_{x\to0}\frac{4x^3+2x^2+6x}{x}$
$\lim_{x\to\infty}\left(\frac{4x^2-5x}{1-3x}\right)$
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