$\frac{x^5+3x-1}{x+3}$
$\frac{1}{n}=\frac{4n-20}{n^2-4n}+\frac{1}{n^2-4n}$
$\int\left(1-\sin^2\left(x\right)\right)\cdot\cos\left(x\right)dx$
$x\cdot y'\:-\:3\:=\:0$
$\left(-12.5\right)\left(-2.25\right)$
$24-2\cdot7-5\cdot8$
$x^2-kx+121=0$
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