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- Integrate by partial fractions
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Multiply the fraction and term in $-3\frac{1}{3}x^3\sin\left(3x\right)$
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$\frac{1}{3}x^3\cos\left(3x\right)-\int-x^3\sin\left(3x\right)dx$
Learn how to solve tabular integration problems step by step online. Find the integral cos(3x)1/3x^3-int(1/3x^3*-3sin(3x))dx. Multiply the fraction and term in -3\frac{1}{3}x^3\sin\left(3x\right). The integral -\int-x^3\sin\left(3x\right)dx results in: -\frac{1}{3}x^3\cos\left(3x\right)+\frac{1}{3}x^{2}\sin\left(3x\right)+\frac{2}{9}x\cos\left(3x\right)-\frac{2}{27}\sin\left(3x\right). Gather the results of all integrals. Combining like terms \frac{1}{3}x^3\cos\left(3x\right) and \left(-\frac{1}{3}\right)x^3\cos\left(3x\right).
