$x^2+4x+40$
$4=\frac{-8+n}{3}$
$\sqrt[3]{5x\sqrt[4]{2x}}$
$2x\:-\:4y\:+\:2\:-\:3x\:+\:2\:+\:2y\:-\:4$
$\frac{d}{dx}\left(4x^2-5=3y^2-6\right)$
$\int\frac{7x+3}{\left(7x^2+6x\right)^5}dx$
$\left(6m^6+8n^6\right)^2$
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