$2=\frac{x+2}{x-6}$
$\frac{x^3-2x^2+4}{x^2}$
$\left(-10\right)\left(-7\right)\left(-8\right)$
$\left(3x\right)^3+64$
$\int\left(x+1\right)\arctan\left(x\right)dx$
$\frac{x^2+2x+1}{x^4-1}$
$\left(\frac{3}{c}\right)^2\left(\frac{9d^2}{2c}\right)^{-3}$
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