Final answer to the problem
$f\left(x\right)=\frac{\sqrt[6]{\left(x^2-2x-63\right)^{5}}}{\sqrt[6]{\left(3x+8\right)^{5}}}$
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Step-by-step Solution
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- Write in simplest form
- Solve by quadratic formula (general formula)
- Find the derivative using the definition
- Simplify
- Find the integral
- Find the derivative
- Factor
- Factor by completing the square
- Find the roots
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1
Apply the property of power of a product in reverse: $a^n\cdot b^n=(a\cdot b)^n$
$f\left(x\right)=\frac{\sqrt[6]{\left(\left(x+7\right)\left(x-9\right)\right)^{5}}}{\sqrt[6]{\left(3x+8\right)^{5}}}$
Learn how to solve product of binomials with common term problems step by step online.
$f\left(x\right)=\frac{\sqrt[6]{\left(\left(x+7\right)\left(x-9\right)\right)^{5}}}{\sqrt[6]{\left(3x+8\right)^{5}}}$
Learn how to solve product of binomials with common term problems step by step online. Simplify the expression f(x)=((x+7)^(5/6)(x-9)^(5/6))/((3x+8)^(5/6)). Apply the property of power of a product in reverse: a^n\cdot b^n=(a\cdot b)^n. Solve the product \left(x+7\right)\left(x-9\right). Subtract the values 7 and -9. Multiply 7 times -9.
Final answer to the problem
$f\left(x\right)=\frac{\sqrt[6]{\left(x^2-2x-63\right)^{5}}}{\sqrt[6]{\left(3x+8\right)^{5}}}$
