$3\left(x+1\right)+2\left(4x+6\right)$
$\frac{x}{8}+5=6\:\frac{1}{8}$
$20\cdot\:\:2^2\cdot\:\:5^5\cdot\:\:3^3y^3$
$\frac{n+1}{n^2-6n+8}$
$2cosx\:=\:3tgx$
$-3\left(5x+8\right)-7\left(5x+3\right)$
$x^2-2<0$
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