$fgh=\left(fg\right)h$
$\int\left(2x-1\right)\ln xdx$
$2-2t\le t-5$
$\left(2xy-10ac^2\right)^3$
$2cos\left(arccos\left(x\right)\right)$
$\frac{60xy}{30x^2y^2}$
$\left(x+4\right)\left(x-3\right)\left(x^2+36\right)$
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