$3+4^2\cdot3-\sqrt{36}+15^0$
$\int sin3x\:sin2x\:dx$
$\left(2x-3\right)-\left(x-5\right)^2$
$\frac{69+77}{2}$
$\left(-26+36:4\right).2-174:\left(-7+1\right)$
$4\sqrt{3}+8cm$
$\frac{3x^2-10x^2+20x-16}{3x-4}$
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