$\frac{\left(x^2\:y^3\right)^4\left(xy^4\right)^{-3}}{x^2y}$
$cot^2\left(x\right)sec\left(x\right)-cos\left(x\right)$
$\sqrt{x^2-36}=8$
$-12,4+6,19-4,601$
$\frac{y^2-16}{4+y}$
$\left(3x^4+\frac{7}{2}\right)\left(3x^4+\frac{3}{5}\right)$
$\frac{36}{1.9}$
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