$\frac{x^2-13x+40}{x+8}$
$\frac{5.5-2}{9-2}$
$3x^2-13x+10$
$\int\left(\frac{1}{3x^2+5}\right)dx$
$2bc+3b-12c-15c+7bc-13b$
$\frac{dx}{dt}=20-\frac{x}{15}$
$\lim_{x\to\infty}\left(\frac{\left(6x^2-9x+8\right)}{\left(3x^2+2\right)}\right)$
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