$6y^2-3+7y\:$
$0.90\cdot2$
$\sqrt[3]{25x^5}$
$8x-56=0$
$-33+-1$
$\lim_{x\to\infty}\left(8x^{\frac{1}{x^2}}\right)$
$\frac{c}{2a}-\frac{c}{3a}$
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