$\frac{3x-2}{x+1}<3$
$\frac{3x^3-3x^2\:}{3x^3+5}$
$\left(3x^2-4+\frac{-10}{x-5}\right)\cdot\left(x-5\right)$
$x^2-1<0$
$4x^4-3x^3+26x^2-27x-90$
$4x^2-9y^2=36$
$\tan2\left(36.86\right)$
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