$3-4-4-4-6+21+7+8$
$6cos\left(x\right)=6cos^2\left(x\right)-2$
$\frac{3x^3}{4x}$
$\left(x^2-x-1+\frac{3}{x+1}\right)-\left(2x^2-3x+5\right)$
$\sqrt{4}-4\le-2\sqrt{4+1}-7$
$\left(2u^4+13u^3-6u^2\right)\left(u-3\right)$
$63.125\left(100\right)$
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