$\int\left(\frac{x\cdot\:\:tan^{-1}\left(x\right)}{\left(1+x^2\right)^{\frac{3}{2}}}\right)$
$8+1$
$8-10-3+11-1$
$3x+8x^2-9x-10$
$\lim_{x\to\infty}\left(\frac{t^4-4t^3}{4}\right)$
$\frac{d}{dz}\left(\sqrt{\frac{\left(xy+z\right)}{yz-x}}+3x\right)$
$\left|+6\right|+\left|+6\right|$
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