$16-8x^{2}$
$9x^2-3x+1$
$\lim_{x\to2}10$
$4x+6y+\left(-4y\right)$
$y=3\ln\left(4x\right)$
$\left(56\right)\:-\:\left(-14\right)\:+\:\left(+6\right)\:$
$\int\frac{\left(4x^2-5x+6\right)}{x-3}dx$
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