$\int\sqrt{16+4t^2}dx$
$y'=e^{6\cdot x+5\cdot y}$
$\left(1+5x\right)^{-\frac{1}{5}}$
$\int\left(\frac{x^2-10x+4}{x^3}\right)dx$
$x^2y^3\cdot2x^3y^2$
$\left(2x^{3}-5x^{2}-6x+15\right)^{1}\times3-2x+41$
$\csc^2x+\cot x-1=0$
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