$\frac{x+3}{\left(x-1\right)\left(x+2\right)}$
$x^2+16x+4$
$\left(6m-4m+10a-5\right)+\left(10m-4m+5a-9\right)$
$5x-3>7-3x$
$\frac{dy}{dt}-y=0$
$x+18=35$
$+-4=7$
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