$5a+3c-b-3c+a$
$4x^2+x^2-xy+3y^2+2xy-3x^2+y$
$\frac{1}{4}x\cdot\:\frac{1}{2}x$
$\left(-2a^2b^3c^4\right).\left(3a^3b^2c^3\right)$
$-3+\left(4-\left(5-2\right)+1\right)$
$\left(xy^2\right)\:+\:\left(xy^2\right)^2$
$35+\left(-55\right)+39\:+7$
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