$\left(2\:x^4\:\frac{-1}{x^2}\right)$
$8a^2+12ab-20a$
$\frac{8a^3-b^3}{2a-b}$
$\int\left(x^2-6x\right)^4\left(x-3\right)dx$
$\frac{n^42n^2-48}{n^2+8}$
$\frac{dy}{dx}=\frac{x+3}{x-3}$
$x^2-8x+16=9$
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