$2\sqrt{1-x}=\sqrt{16-3x}-1$

$\left(-23\right)\cdot\left(+12\right)$

$\frac{1}{36}\cdot\left(2187a+686b\right)$

$4p^2+5.5m+2.5p^2-m+3m$

$12\cdot27$

$\frac{x}{x-1}+\frac{1}{6x-1}=\frac{1}{\left(x-1\right)\left(6x-1\right)}$

$\lim_{x\to\infty}\frac{x\:\ln\left(x\right)}{x^2-1}$