$x^0y^{-3}$
$4y^2x+4x=2xy$
$\left(6x^2+10\right)\left(6x^2-10\right)$
$x^2\:14x+49$
$\left(-4x+3\right)\left(3x-4\right)$
$\lim_{x\to\infty}\left(\frac{x^2+5x+15}{x^3-5x^2+16}\right)$
$\frac{dy}{dx}=\left(5x^4-1\right)\left(2x^2-5\right)$
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