$\frac{d^2}{dx^2}\left(2\cos\left(x\right)-3\sin\left(x\right)\right)$
$\frac{1}{16}+\frac{1}{2}m^2+m^2$
$\frac{8x^5+4x^3+8x^2+4x+16}{2x^3+x^2+3}$
$c=\sec x\cdot\cot x+\cos x$
$-64\cdot\left(7+16\right)$
$4^2\:+\:2\:.\:4\:.5+5^2$
$.\sqrt{169}.2-\sqrt[5]{32}+3^2$
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