Final answer to the problem
$\frac{\left(k^3-1\right)\left(k+l\right)^2}{\left(k+1\right)\left(k^2+kl+l^2\right)}$
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Step-by-step Solution
How should I solve this problem?
- Choose an option
- Write in simplest form
- Solve by quadratic formula (general formula)
- Find the derivative using the definition
- Simplify
- Find the integral
- Find the derivative
- Factor
- Factor by completing the square
- Find the roots
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1
Calculate the power $1^3$
$\frac{\frac{k^3- 1}{k+1}}{\frac{k^2+kl+l^2}{\left(k+l\right)^2}}$
Learn how to solve simplification of algebraic fractions problems step by step online.
$\frac{\frac{k^3- 1}{k+1}}{\frac{k^2+kl+l^2}{\left(k+l\right)^2}}$
Learn how to solve simplification of algebraic fractions problems step by step online. Simplify the expression ((k^3-*1^3)/(k+1))/((k^2+kll^2)/((k+l)^2)). Calculate the power 1^3. Multiply -1 times 1. We can simplify the quotient of fractions \frac{\frac{k^3-1}{k+1}}{\frac{k^2+kl+l^2}{\left(k+l\right)^2}} by inverting the second fraction and multiply both fractions.
Final answer to the problem
$\frac{\left(k^3-1\right)\left(k+l\right)^2}{\left(k+1\right)\left(k^2+kl+l^2\right)}$
