$-\frac{3}{2}-\frac{5}{2}$

$\frac{\sin b}{1-\cos b}$

$\lim_{x\to infinity}sin\:x\:-\:cos\:x$

$\frac{\frac{-3x^2}{2\sqrt[2]{4-3x}}}{x^4}$

$r^2-6r+9=0$

$16t^2+16t+32$

$\frac{1-\sin\left(x\right)}{\cos\left(x\right)}\cdot\cot\left(x\right)=\frac{1}{\sin\left(x\right)}$