$\int\left(3z-3\right)\ln\left(z\right)dz$
$\int r^2\left(\frac{r^3}{15}-3\right)^4dr$
$\left(+b\right)\left(d-c\right)\left(b-a\right)\left(m-p\right);\:a=1;\:b=2;\:c=3;\:d=4;\:m=\frac{1}{2};\:p=\frac{1}{4}\:$
$-4\left(-11+4n\right)-3\left(-n+9\right)$
$6+\sqrt{9}\left(3+4\right)$
$b+a+c-a-c$
$4\left(k+9\right)$
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