$\left(16f^3\right)^{\frac{7}{4}}$
$17-0,5\left(-1\right)$
$-20+5f=20$
$13^2\cdot13^{-2}$
$\lim_{x\to-\infty\:}\frac{\sqrt{x^2+1}}{x+2}$
$\frac{1}{6}\frac{dy}{dx}-y=\frac{e^{5x}}{6}$
$\int_1^{+\infty\:}\left(\frac{1}{x^3\sqrt{x^2+1}}\right)\:dx$
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