$\int\sqrt[3]{\left(x^2\right)}dx$
$16-\left(1+x\right)^2$
$-16x^2+25=25-15x^2$
$\sqrt[3]{2n^2}-\sqrt[3]{2m^2}$
$2y=x+1$
$\lim_{x\to0}\left(\frac{ln^{\frac{1}{x}}}{\frac{1}{tanx}}\right)$
$-4\:\left(\:8:\left(-11+7\right)+\left(-2+6\right)\right)$
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