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- Integrate by partial fractions
- Product of Binomials with Common Term
- FOIL Method
- Integrate by substitution
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- Integrate using tabular integration
- Integrate by trigonometric substitution
- Weierstrass Substitution
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Multiply and divide the fraction $\frac{\sqrt[3]{x^6+8}}{4x^2+\sqrt{3x^4+1}}$ by the conjugate of it's denominator $4x^2+\sqrt{3x^4+1}$
Learn how to solve factor by difference of squares problems step by step online.
$\frac{\sqrt[3]{x^6+8}}{4x^2+\sqrt{3x^4+1}}\frac{4x^2-\sqrt{3x^4+1}}{4x^2-\sqrt{3x^4+1}}$
Learn how to solve factor by difference of squares problems step by step online. Rationalize and simplify the expression ((x^6+8)^(1/3))/(4x^2+(3x^4+1)^(1/2)). Multiply and divide the fraction \frac{\sqrt[3]{x^6+8}}{4x^2+\sqrt{3x^4+1}} by the conjugate of it's denominator 4x^2+\sqrt{3x^4+1}. Multiplying fractions \frac{\sqrt[3]{x^6+8}}{4x^2+\sqrt{3x^4+1}} \times \frac{4x^2-\sqrt{3x^4+1}}{4x^2-\sqrt{3x^4+1}}. Solve the product of difference of squares \left(4x^2+\sqrt{3x^4+1}\right)\left(4x^2-\sqrt{3x^4+1}\right).